In the two equations below, solve for x and y and choose the correct relation. I. x^2 - 13x + 42 = 0 II. y^2 - 11y + 30 = 0

Question

Accepted Answer

x ≥ y. I: (x−6)(x−7)=0 → x = 6, 7. II: (y−5)(y−6)=0 → y = 5, 6. Smallest x (6) = largest y (6); every x ≥ every y with equality at 6, so x ≥ y.

In the two equations below, solve for $x$ and $y$ and choose the correct relation. I. $x^{2} - 13 x + 42 = 0$
II. $y^{2} - 11 y + 30 = 0$