Solve both equations and find the relation between $x$ and $y$ . I. $3 x^{2} - 22 x + 40 = 0$
II. $3 y^{2} - 16 y + 20 = 0$

Question

Solve both equations and find the relation between x and y. I. 3x² − 22x + 40 = 0 II. 3y² − 16y + 20 = 0

Accepted Answer

x ≥ y. I: (3x − 10)(x − 4) = 0 → x = 10/3, 4. II: (3y − 10)(y − 2) = 0 → y = 10/3, 2. The smallest x equals the largest y (10/3), so x ≥ y.

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