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Solve both equations and find the relation between $x$ and $y$ . I. $x^{2} - 5 x + 6 = 0$
II. $y^{2} - 15 y + 54 = 0$

Competition practiceQuadratic Comparison

A $x$ ≥ $y$
B $x > y$
C $x$ ≤ $y$
D $x < y$

Step-by-Step Solution

I:

(x - 2) (x - 3)

→

x = 2

, 3. II:

(y - 6) (y - 9)

→

y = 6

, 9. The largest

x

(3) is less than the smallest

y

(6). So

x < y

.

Answer: D)

x < y

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