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Solve both equations and choose the correct relation. I. $x^{2} + 9 x + 20 = 0$
II. $y^{2} - 4 = 0$

Competition practiceQuadratic Comparison

A $x < y$
B $x > y$
C $x$ ≤ $y$
D $x$ ≥ $y$

Step-by-Step Solution

I:

(x + 4) (x + 5) = 0

gives

x = - 4

or -5. II:

y^{2} = 4

gives

y = 2

or -2. Largest

x

(-4) < smallest

y

(-2), so

x < y

in every case.

Answer: A)

x < y

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