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Solve the pair and decide how $x$ compares with $y$ . I. $x^{2} - 31 x + 240 = 0$
II. $y^{2} - 33 y + 272 = 0$

Competition practiceQuadratic Comparison

A $x < y$
B $x$ ≥ $y$
C $x$ ≤ $y$
D $x > y$

Step-by-Step Solution

x = 15

or 16;

y = 16

or 17.

x

never exceeds

y

and

x = y = 16

is possible, so

x

≤

y

.

Answer: C)

x

≤

y

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