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Solve and compare: I. $x^{2} + 13 x + 42 = 0$
II. $y^{2} + 9 y + 18 = 0$

Competition practiceQuadratic Comparison

A $x$ ≤ $y$
B $x > y$
C $x$ ≥ $y$
D $x < y$

Step-by-Step Solution

x = - 6

or −7;

y = - 3

or −6.

x

is never greater than

y

and

x = y = - 6

is possible, so

x

≤

y

.

Answer: A)

x

≤

y

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