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Solve and relate: I. $2 x^{2} - 17 x + 36 = 0$
II. $3 y^{2} - 10 y - 8 = 0$

Competition practiceQuadratic Comparison

A $x$ ≤ $y$
B $x < y$
C $x$ ≥ $y$
D $x > y$

Step-by-Step Solution

I:

(2 x - 9) (x - 4) = 0

→

x = 4.5

, 4. II:

(3 y + 2) (y - 4) = 0

→

y = 4

, −2/3. The smallest

x

equals the largest

y

(4), so

x

≥

y

.

Answer: C)

x

≥

y

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