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Solve both equations and state the relation between $x$ and $y$ . I. $x^{2} - 9 x + 18 = 0$
II. $y^{2} - 14 y + 48 = 0$

Competition practiceQuadratic Comparison

A $x$ ≤ $y$
B $x < y$
C $x > y$
D $x$ ≥ $y$

Step-by-Step Solution

x = 3

or 6;

y = 6

or 8. No

x

exceeds any

y

, and

x = y = 6

is possible, so

x

≤

y

.

Answer: A)

x

≤

y

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