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Solve the two equations and determine the relation between $x$ and $y$ .
I. $x^{2} - 5 x + 6 = 0$
II. $y^{2} - 4 y + 3 = 0$

Competition practiceQuadratic Comparison

A $x > y$
Brelationship cannot be established
C $x < y$
D $x$ ≥ $y$

Step-by-Step Solution

x = 2

or 3;

y = 1

or 3. Since

x = 2 > y = 1

but

x = 2 < y = 3

, no fixed relation holds.

Answer: B) relationship cannot be established

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