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A and B together do 3 times as much as C, and B and C together do twice as much as A. All three finish a job in 12 days. How long would A take alone?

Competition practiceTime & Work / Pipes

A48 days
B36 days
C28 4/5 days
D24 days

Step-by-Step Solution

a + b = 3 c

gives the total

4 c = \frac{1}{12}, c = \frac{1}{48} . b + c = 2 a

with

a + b = 3 c : 3 a = 4 c, a = \frac{1}{36}

.

Answer: B) 36 days

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