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The angle of elevation of the top of a tower from a point A on the ground is 45°. On walking 30 m from A straight towards the tower, to B, it becomes 60°. Find the height of the tower.

Competition practiceTrigonometry
  • A15(3 + √3) m
  • B15(3 − √3) m
  • C30√3 m
  • D15(√3 + 1) m

Step-by-Step Solution

h cot 45° − h cot 60° = 30, i.e. h(1 − 1/√3) = 30. So h = 30√3/(√3 − 1) = 15√3(√3 + 1) = 15(3 + √3) m ≈ 71 m.
Answer: A) 15(3 + √3) m

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