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Two people stand on the same side of a 50 m tall tower, in line with its foot. They see its top at elevations of 30° and 45°. How far apart are they?

Competition practiceTrigonometry
  • A50(√3 − 1) m
  • B50(√3 + 1) m
  • C50√3 m
  • D50 m

Step-by-Step Solution

Distances: 50 cot 30° = 50√3 and 50 cot 45° = 50. Difference = 50(√3 − 1) m ≈ 36.6 m.
Answer: A) 50(√3 − 1) m

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