- A100(√3 − 1) m
- B200 m
- C100(√3 + 1) m
- D100√3 m
Step-by-Step Solution
Distances: and . Opposite sides, so add: m.
Answer: C) 100(√3 + 1) m
Two ships are on opposite sides of a 100 m high lighthouse. From its top, their angles of depression are 30° and 45°. Find the distance between the ships.
Competition practiceTrigonometry
Master this topic in 30 minutes a day.
Don't just memorise the answer — build a daily practice habit.
Practice 5 Similar Questions Free →All Trigonometry practice questions
More Trigonometry practice
From the top of a 200 m high cliff, the angles of depression of two boats on the same…A tree breaks in a storm. The broken part bends over so that its top touches the ground…A flagstaff stands on top of a 20 m high building. From a point on the ground, the…A 1.5 m tall boy stands some distance from a 30 m tall building. As he walks towards the…From the top of a 60 m high building, the angles of depression of the top and the bottom…