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₹12000 is invested for two years with interest compounded annually. The rate for the first year is 10%, and at the end of the second year the investment stands at ₹14784. The rate for the second year is what percent?

Competition practiceRatio, Percentage & Commercial Math
  • A11.6
  • B13.2
  • C12
  • D14

Step-by-Step Solution

After one year the money is = ₹13200, and 14784/13200 = 1.12, so the second year's rate is 12%. The total growth is 14784/12000 = 1.232; subtracting the first year's 10% from that 23.2% gives 13.2%, and halving it gives 11.6% — but growth factors multiply, they do not add, and the second year's rate acts on ₹13200, not on ₹12000.
Answer: C) 12

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