Refer to the series 8 B R 4 % W 6 F 2 D @ 9 J 7 K * 3 5 T. Suppose every digit in it were replaced by the letter standing at that place in the English alphabet, so that 1 becomes A, 2 becomes B and so on. How many vowels would the series then hold?

The digits are 8, 4, 6, 2, 9, 7, 3 and 5, and they turn into H, D, F, B, I, G, C and E. Of these only I (from 9) and E (from 5) are vowels. The letters already in the series — B, R, W, F, D, J, K and T — hold no vowel at all, so the total is 2. Answering 3 or 4 comes of counting Y-like or near-vowel letters among the new ones, and 1 of spotting only the first of the two.