How many times are the hands in one straight line strictly between the time on clock A and the time on clock B, the same afternoon?

A shows 12:00 (hands together) and B shows 6:00 (hands opposite); neither end counts. The hands are in line every $32\frac{8}{11}$ min, so the 6 hours hold $\frac{360}{360/11}=11$ intervals: 12 line-ups counting both ends, 10 strictly inside. (11 and 12 include the end points.)