The bars of A are rearranged to make B. Rearrange the bars of C in the same way.

B uses exactly the bars of A, put in order from the shortest on the left to the tallest on the right. Doing the same to C gives short, medium-short, medium-tall, tallest: (a). (b) puts them in order from tallest to shortest, (c) just reads C backwards and (d) swaps neighbouring bars.