Only the relations written below are known.
Statement: C ≥ D ≥ E < F
Conclusions: I. C > E
II. C ≥ E
Which conclusion follows?

The link E < F points away from the rest and plays no part in comparing C with E, so the question turns entirely on C ≥ D ≥ E. Two non-strict links in the same sense compose to a non-strict result, giving C ≥ E, so II follows. I claims the strict relation C > E, which would need at least one strict link between C and E, and there is none: C = D = E = 4, F = 9 satisfies every statement and makes C > E false. So only II follows. 'Both' is what a solver gets by reading the run of ≥ signs as though it produced >, or by letting the unrelated strict link E < F supply strictness it cannot contribute. 'Neither' overlooks that C ≥ E is genuinely established.