- AThe share of the chain's patients seen at its slowest clinic was not appreciably smaller in the second year than in the first
- BEach of the three clinics saw more patients in the second year than in the first
- CNo patient of the chain waited longer than 38 minutes at any time in the second year
- DThe chain's clinics were open on the same number of days in each of the two years
Step-by-Step Solution
The chain's average is the three clinics' waits weighted by how many patients each saw, so it can fall without a single clinic quickening if patients simply shift away from the slow one — a bus route altered, a clinic closed a day a week, a new road bringing patients to the fastest branch. The partner's conclusion therefore rests on the mix having stayed put, and denying that assumption dissolves his case. Each clinic seeing more patients is neither needed nor helpful, since the mix could still shift. No patient waiting above 38 minutes would make 38 an unusually high average rather than a mean. And equal opening days leave the distribution of patients across the three untouched.
Answer: A) The share of the chain's patients seen at its slowest clinic was not appreciably smaller in the second year than in the first