- A10√3
- B20√3
- C30√3
- D40√3
Step-by-Step Solution
The distances are 30/tan30° = 30√3 and 30/tan60° = 10√3, so the observer walked 30√3 − 10√3 = 20√3 metres.
Answer: B) 20√3
A tower is 30 m high. As an observer walks straight towards its foot, the angle of elevation of the top changes from 30° to 60°. The distance walked, in metres, is:
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