- A150(√3 − 1) m/min
- B75(√3 + 1) m/min
- C75(√3 − 1) m/min
- D75√3 m/min
Step-by-Step Solution
The boat's distances from the foot of the cliff are 150/tan30° = 150√3 m and 150/tan45° = 150 m. It covers 150√3 − 150 = 150(√3 − 1) m in 2 minutes, so the speed is 75(√3 − 1) m/min ≈ 54.9 m/min.
Answer: C) 75(√3 − 1) m/min