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If A + B + C = 180°, then tanA + tanB + tanC equals:

Competition practiceTrigonometry
  • A0
  • BtanA·tanB·tanC
  • C1
  • DcotA + cotB + cotC

Step-by-Step Solution

Since A + B = 180° − C, we get tan(A + B) = −tanC, that is (tanA + tanB)/(1 − tanA·tanB) = −tanC. Cross-multiplying: tanA + tanB = −tanC + tanA·tanB·tanC, which rearranges to tanA + tanB + tanC = tanA·tanB·tanC. Check with A = B = C = 60°: both sides equal 3√3 ≈ 5.196.
Answer: B) tanA·tanB·tanC

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