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The expression (1 + ta $n^{2}$ A) / (1 + co $t^{2}$ A) simplifies to:

Competition practiceTrigonometry

Ata $n^{2}$ A
Bco $t^{2}$ A
Cse $c^{2}$ A
D1

Step-by-Step Solution

The numerator is se

c^{2}

A and the denominator is cose

c^{2}

A, so the ratio is si

n^{2}

A/co

s^{2}

A

= ta

n^{2}

A.

Answer: A) ta

n^{2}

A

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