- A15 m
- B30√3 m
- C10√3 m
- D15√3 m
Step-by-Step Solution
The two shadows are h·cot30° = h√3 and h·cot60° = h/√3. Their difference is h(√3 − 1/√3) = 2h/√3 = 30, so h = 15√3 ≈ 25.98 m.
Answer: D) 15√3 m
The shadow of a vertical tower on level ground is 30 m longer when the sun's altitude is 30° than when it is 60°. The height of the tower is:
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