- A(40 + 20√3) m
- B(60√3 − 40) m
- C(40 + 60√3) m
- D100 m
Step-by-Step Solution
The man is 40·cot45° = 40 m from the shorter tower and 60·cot30° = 60√3 ≈ 103.9 m from the taller one. Because he stands between them the two distances add, giving 40 + 60√3 ≈ 143.9 m. Subtracting them would put both towers on the same side of him, and 100 m is just the sum of the two heights, which has nothing to do with the ground distance.
Answer: C) (40 + 60√3) m