A ball is thrown upward and its height (in metres) after t seconds is h = -5t^2 + 20t. Completing the square gives h = -5(t - 2)^2 + 20. What is the maximum height reached by the ball?

Question

Accepted Answer

20. Maximum of -5(t - 2)^2 + 20 occurs when (t - 2)^2 = 0, i.e. t = 2 s, giving h = 20 m.

A ball is thrown upward and its height (in metres) after $t$ seconds is
$h = - 5 t^{2} + 20 t$ . Completing the square gives $h = - 5 (t - 2)^{2} + 20$ .
What is the maximum height reached by the ball?

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More Class 10 Completing the Square practice

A ball is thrown upward and its height (in metres) after t seconds ish=−5t2+20t. Completing the square gives h=−5(t−2)2+20.What is the maximum height reached by the ball?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Completing the Square practice

A ball is thrown upward and its height (in metres) after $t$ seconds is
$h = - 5 t^{2} + 20 t$ . Completing the square gives $h = - 5 (t - 2)^{2} + 20$ .
What is the maximum height reached by the ball?