The product of two consecutive positive integers is 156. If the smaller integer is x, then x^2 + x - 156 = 0. Solve by completing the square to find the two integers.

Question

Accepted Answer

12 and 13. x^2 + x = 156, add 1/4: (x + 1/2)^2 = 156.25 = 625/4, x + 1/2 = 25/2, x = 12. Integers are 12 and 13.

The product of two consecutive positive integers is 156.
If the smaller integer is $x$ , then $x^{2} + x - 156 = 0$ .
Solve by completing the square to find the two integers.

Step-by-Step Solution

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More Class 10 Completing the Square practice

The product of two consecutive positive integers is 156.If the smaller integer is x, then x2+x−156=0.Solve by completing the square to find the two integers.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Completing the Square practice

The product of two consecutive positive integers is 156.
If the smaller integer is $x$ , then $x^{2} + x - 156 = 0$ .
Solve by completing the square to find the two integers.