An iron pipe (hollow cylinder) has outer radius 5 cm, inner radius 3 cm and length 14 cm. It is melted and recast into a solid cylinder of radius 4 cm. Find the height of the solid cylinder (in cm).

Question

Accepted Answer

14. Metal volume = π*(5^2 - 3^2)*14 = π*(25-9)*14 = π*16*14 = 224 π. Solid cylinder: π*4^2*h = 224 π => 16h = 224 => h = 14 cm.

An iron pipe (hollow cylinder) has outer radius 5 cm, inner radius 3 cm and length 14 cm. It is melted and recast into a solid cylinder of radius 4 cm.
Find the height of the solid cylinder (in cm).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Conversion of Solids practice

An iron pipe (hollow cylinder) has outer radius 5 cm, inner radius 3 cm and length 14 cm. It is melted and recast into a solid cylinder of radius 4 cm.Find the height of the solid cylinder (in cm).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Conversion of Solids practice

An iron pipe (hollow cylinder) has outer radius 5 cm, inner radius 3 cm and length 14 cm. It is melted and recast into a solid cylinder of radius 4 cm.
Find the height of the solid cylinder (in cm).