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Two mobile towers stand at P(3, 6) and Q(−1, 4) on a grid marked in kilometres. A relay mast must be built somewhere on the -axis, the same distance from each tower. Where should it stand?

Class 10Coordinate GeometryGeometry — Coordinates
  • A(0, 7)
  • B(7, 0)
  • C(0, 5)
  • D(0, -7)

Step-by-Step Solution

A point on the -axis is (0, ). Equate squared distances: → → → → . The mast goes at (0, 7), and both distances are km. Averaging the two -coordinates to get (0, 5) is the common error — that is the midpoint of PQ, which is not on the -axis. (7, 0) has the axes swapped.
Answer: A) (0, 7)

Key idea: Distance formula

**Distance** between two points P₁, ₁) and Q₂, ₂):

**PQ = **

This is just the Pythagoras theorem applied to the right triangle formed with horizontal and vertical legs.

**Example**: Distance between (3, 4) and (7, 1).
= .

**Special distance from origin**: distance of from (0, 0) is .

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