In triangle ABC, DE || BC with D on AB and E on AC. If AD = x, DB = x + 2, AE = x - 1 and EC = x. Using AD/DB = AE/EC (from the similarity DE || BC gives), find x.

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2. AD/DB = AE/EC: x/x+2 = x-1/x. Cross-multiply: x^2 = (x-1)(x+2) = x^2 + x - 2. So 0 = x - 2, x = 2.

In triangle $A BC, D E ∣∣ BC$ with $D$ on $A B$ and $E$ on $A C$ . If $A D = x, D B = x + 2, A E = x - 1$ and $EC = x$ .
Using $\frac{A D}{D B} = \frac{A E}{EC}$ (from the similarity $D E ∣∣ BC$ gives), find $x$ .

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More Class 10 Criteria for Similarity practice

In triangle ABC,DE∣∣BC with D on AB and E on AC. If AD=x,DB=x+2,AE=x−1 and EC=x.Using DBAD​=ECAE​ (from the similarity DE∣∣BC gives), find x.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Criteria for Similarity practice

In triangle $A BC, D E ∣∣ BC$ with $D$ on $A B$ and $E$ on $A C$ . If $A D = x, D B = x + 2, A E = x - 1$ and $EC = x$ .
Using $\frac{A D}{D B} = \frac{A E}{EC}$ (from the similarity $D E ∣∣ BC$ gives), find $x$ .