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Which value of $c$ makes $x^{2} + 6 x + c = 0$ have no real roots?

Class 10Discriminant and Nature of RootsAlgebra — Quadratics

A $c = 10$
B $c = 9$
C $c = 8$
D $c = 5$

Step-by-Step Solution

No real roots need

D < 0 : 36 - 4 c < 0

, so

c > 9

. Among the options only

c = 10

satisfies this.

Answer: A)

c = 10

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