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Find a point on the -axis which is equidistant from A(2, -5) and B(-2, 9).

Class 10Distance FormulaGeometry — Coordinates
  • A(-7, 0)
  • B(7, 0)
  • C(0, -7)
  • D(2, 0)

Step-by-Step Solution

Let point be , 0). Equate squared distances: . Expand: , so . Point is (-7, 0).
Answer: A) (-7, 0)

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