The point (x, 7) is at a distance of 85 units from the point (2, 1).
Find a positive value of x.
Class 10Distance FormulaGeometry — Coordinates
Step-by-Step Solution
(x−2)2+(7−1)2=85. So
(x−2)2+36=85, giving
(x−2)2=49,x−2=7,x=9 (positive value).
Answer: B) 9
All Distance Formula practice questions
More Class 10 Distance Formula practice
Find a point on the x-axis which is equidistant from A(2, -5) and B(-2, 9).If the distance between the points (3, a) and (3, 5) is 12 units and a < 5, find a.Show by computing the three side lengths whether the triangle with vertices P(1, 1),…The points A(1, 2), B(4, 2) and C(4, 6) form a triangle. Using the distance formula for…Check whether the points (1, 5), (2, 3) and (-2, -11) are collinear by comparing…