The present ages of a father and son add up to 65 years. Five years ago, the father was 4 times as old as the son, giving F - 4S = -15. Using elimination on F + S = 65 and F - 4S = -15, find the son's present age (in years).

Question

Accepted Answer

16. Subtract second from first: 5S = 80, so S = 16 years. (Then F = 49; five years ago 44 = 4 x 11.)

The present ages of a father and son add up to 65 years. Five years ago, the father was 4 times as old as the son, giving F - 4S = -15.
Using elimination on F + S = 65 and F - 4S = -15, find the son's present age (in years).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Elimination Method practice

The present ages of a father and son add up to 65 years. Five years ago, the father was 4 times as old as the son, giving F - 4S = -15.Using elimination on F + S = 65 and F - 4S = -15, find the son's present age (in years).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Elimination Method practice

The present ages of a father and son add up to 65 years. Five years ago, the father was 4 times as old as the son, giving F - 4S = -15.
Using elimination on F + S = 65 and F - 4S = -15, find the son's present age (in years).