A cone of base radius 8 cm and height 12 cm is cut by a plane parallel to the base such that the top small cone has height 3 cm. Find the volume of the frustum left, in cm^3 (use π = 3.14).

Question

Accepted Answer

791.28. Big cone V = 1/3*3.14*64*12 = 803.84. Small cone radius = 3/12*8 = 2; V = 1/3*3.14*4*3 = 12.56. Frustum = 803.84 - 12.56 = 791.28 cm^3.

A cone of base radius 8 cm and height 12 cm is cut by a plane parallel to the base such that the top small cone has height 3 cm.
Find the volume of the frustum left, in $cm^{3}$ (use π = 3.14).

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More Class 10 Frustum of a Cone practice

A cone of base radius 8 cm and height 12 cm is cut by a plane parallel to the base such that the top small cone has height 3 cm.Find the volume of the frustum left, in cm3 (use π = 3.14).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Frustum of a Cone practice

A cone of base radius 8 cm and height 12 cm is cut by a plane parallel to the base such that the top small cone has height 3 cm.
Find the volume of the frustum left, in $cm^{3}$ (use π = 3.14).