A frustum of a cone has radii 15 cm and 5 cm and height 24 cm. Find its total surface area, in cm^2 (use π = 22/7). (slant height = √24^2 + 10^2) (CSA = curved surface area, TSA = total surface area)

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Accepted Answer

2420. l = √576 + 100 = √676 = 26 cm. TSA = π*l*(R+r) + π*R^2 + π*r^2 = 22/7[26*20 + 225 + 25] = 22/7[520 + 250] = 22/7*770 = 22*110 = 2420 cm^2.

A frustum of a cone has radii 15 cm and 5 cm and height 24 cm.
Find its total surface area, in $cm^{2}$ (use π = $\frac{22}{7}$ ). (slant height = $2 4^{2} + 1 0^{2}$ ) (CSA = curved surface area, TSA = total surface area)

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More Class 10 Frustum of a Cone practice

A frustum of a cone has radii 15 cm and 5 cm and height 24 cm.Find its total surface area, in cm2 (use π = 722​). (slant height = 242+102​) (CSA = curved surface area, TSA = total surface area)

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Frustum of a Cone practice

A frustum of a cone has radii 15 cm and 5 cm and height 24 cm.
Find its total surface area, in $cm^{2}$ (use π = $\frac{22}{7}$ ). (slant height = $2 4^{2} + 1 0^{2}$ ) (CSA = curved surface area, TSA = total surface area)