An open bucket is a frustum whose top radius is 24 cm, bottom radius 10 cm and depth 48 cm. Find the area of metal sheet needed to make it (curved surface and the closed bottom only), in cm². (Take \π = 3.14 .)

Question

Accepted Answer

5652. l = √48^2 + 14^2 = √2500 = 50 cm. Curved surface = 3.14 × 50 × 34 = 5338 cm²; bottom = 3.14 × 10² = 314 cm². Total = 5652 cm². 5338 forgets the bottom; 7460.64 also adds the open top, which needs no sheet; 5438.48 uses the depth 48 cm in place of the slant height 50 cm.

An open bucket is a frustum whose top radius is 24 cm, bottom radius 10 cm and depth 48 cm. Find the area of metal sheet needed to make it (curved surface and the closed bottom only), in $cm^{2}$ . (Take $π = 3.14.$ )

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More Class 10 Frustum of a Cone practice

An open bucket is a frustum whose top radius is 24 cm, bottom radius 10 cm and depth 48 cm. Find the area of metal sheet needed to make it (curved surface and the closed bottom only), in cm2. (Take π=3.14.)

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Frustum of a Cone practice

An open bucket is a frustum whose top radius is 24 cm, bottom radius 10 cm and depth 48 cm. Find the area of metal sheet needed to make it (curved surface and the closed bottom only), in $cm^{2}$ . (Take $π = 3.14.$ )