A shopkeeper in Pune has two ropes of length 84 m and 120 m. He wants to cut both into pieces of equal length with no rope left over, making the pieces as long as possible. What length (in metres) should each piece be?

Question

Accepted Answer

12. Longest equal length = HCF(84, 120). 84 = 2^2 x 3 x 7, 120 = 2^3 x 3 x 5. HCF = 2^2 x 3 = 12 m.

A shopkeeper in Pune has two ropes of length 84 m and 120 m. He wants to cut both into pieces of equal length with no rope left over, making the pieces as long as possible. What length (in metres) should each piece be?

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