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The HCF of 65 and 117 can be expressed as 65m - 117. The value of m is:

Class 10Fundamental Theorem of ArithmeticNumber Systems

A3
B4
C1
D2

Step-by-Step Solution

65 =

5 \times 13, 117 = 9 \times 13

, so HCF = 13. Then

65 m - 117 = 13

gives

65 m = 130

, so

m = 2

.

Answer: D) 2

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