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Find the smallest number which when divided by 15, 20 and 25 leaves no remainder.

Class 10Fundamental Theorem of ArithmeticNumber Systems

A300
B600
C330
D270

Step-by-Step Solution

Smallest such number = LCM(15, 20, 25).

15 = 3 \times 5, 20 = 2^{2} \times 5, 25 = 5^{2}

. LCM =

2^{2} \times 3 \times 5^{2} = 300

.

Answer: A) 300

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