Two ropes are 48 m and 60 m long. A shopkeeper in Jaipur wants to cut both into pieces of equal length, with no rope wasted, using the longest possible piece length. What is the length of each piece (in metres)?

Question

Accepted Answer

12. Longest equal piece = HCF(48, 60). 48 = 2^4 x 3, 60 = 2^2 x 3 x 5; HCF = 2^2 x 3 = 12 m.

Two ropes are 48 m and 60 m long. A shopkeeper in Jaipur wants to cut both into pieces of equal length, with no rope wasted, using the longest possible piece length.
What is the length of each piece (in metres)?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 HCF and LCM practice

Two ropes are 48 m and 60 m long. A shopkeeper in Jaipur wants to cut both into pieces of equal length, with no rope wasted, using the longest possible piece length.What is the length of each piece (in metres)?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 HCF and LCM practice

Two ropes are 48 m and 60 m long. A shopkeeper in Jaipur wants to cut both into pieces of equal length, with no rope wasted, using the longest possible piece length.
What is the length of each piece (in metres)?