From the top of a 60 m high tower in Delhi, the angle of depression of a parked car is 30°. The car then drives toward the tower and stops where the depression becomes 60°. How far (in m) did the car move toward the tower?

Question

Accepted Answer

40 √3. Far: tan 30 = 60/d1 => d1 = 60 √3. Near: tan 60 = 60/d2 => d2 = 60√3 = 20 √3. Moved = 60 √3 - 20 √3 = 40 √3 m.

From the top of a 60 m high tower in Delhi, the angle of depression of a parked car is 30°.
The car then drives toward the tower and stops where the depression becomes 60°.
How far (in m) did the car move toward the tower?

Step-by-Step Solution

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More Class 10 Heights and Distances practice

From the top of a 60 m high tower in Delhi, the angle of depression of a parked car is 30°.The car then drives toward the tower and stops where the depression becomes 60°.How far (in m) did the car move toward the tower?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Heights and Distances practice

From the top of a 60 m high tower in Delhi, the angle of depression of a parked car is 30°.
The car then drives toward the tower and stops where the depression becomes 60°.
How far (in m) did the car move toward the tower?