The angle of elevation of the top of a tower from a point A on the ground is 30°. On walking 30 m toward the tower to point B, the angle of elevation becomes 60°. Find the height of the tower (in m). (Take √(3) = 1.732.)

Question

Accepted Answer

25.98. Let height h, BB' = x. tan60 = h/x => x = h√3. tan30 = h/x+30 => x+30 = h √3. So h √3 - h√3 = 30 => 2h√3 = 30 => h = 15 √3 = 15 x 1.732 = 25.98 m.

The angle of elevation of the top of a tower from a point A on the ground is 30°.
On walking 30 m toward the tower to point B, the angle of elevation becomes 60°.
Find the height of the tower (in m). (Take √(3) = 1.732.)

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Heights and Distances practice

The angle of elevation of the top of a tower from a point A on the ground is 30°.On walking 30 m toward the tower to point B, the angle of elevation becomes 60°.Find the height of the tower (in m). (Take √(3) = 1.732.)

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Heights and Distances practice

The angle of elevation of the top of a tower from a point A on the ground is 30°.
On walking 30 m toward the tower to point B, the angle of elevation becomes 60°.
Find the height of the tower (in m). (Take √(3) = 1.732.)