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A right triangle has its two legs equal in length. For one of its acute angles θ, what is the value of sin θ + cos θ?

Class 10Introduction to TrigonometryTrigonometry
  • A1
  • B
  • C2
  • D

Step-by-Step Solution

Equal legs make both acute angles 45°, so sin θ = cos θ = . Their sum is (about 1.41), not 1.
Answer: D)

Key idea: Why ratios — and not lengths

Two right triangles with the same acute angle θ are SIMILAR (Class 10 ch. 6 — AA criterion: both have a right angle and the angle θ).

Similar triangles → corresponding sides in fixed ratio.
So the ratio (opposite / hypotenuse) takes the SAME value in any right triangle with angle θ — regardless of how big the triangle is.

That's why sin θ, cos θ, tan θ are FUNCTIONS of the angle alone — they're well-defined.

This is the fundamental reason trigonometry works as a clean theory.

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If cot θ = 8/15 for an acute angle θ, find sec θ.If sec θ = 2 for an acute angle θ, find tan θ.If sin θ = 2/3 for an acute angle θ, find cos θ.If sin θ = 12/37 for an acute angle θ, find the value of cos θ − sin θ.If tan θ = 3/4 for an acute angle θ, find the value of 1 - θ/1 + θ.