Net weights (in grams) of 50 packets of tea from a Nashik packing unit: 88-100: 6, 100-112: 11, 112-124: 15, 124-136: 12, 136-148: 6. The class width is 12. Using the step-deviation method with a = 118, find the mean weight.

Question

Accepted Answer

118.24. Class marks 94, 106, 118, 130, 142 give u_i = -2, -1, 0, 1, 2 . f_i u_i = -12 - 11 + 0 + 12 + 12 = 1 , f_i = 50 . Mean = 118 + 12 (1/50 ) = 118 + 0.24 = 118.24 g. "118.02" forgets to multiply by h = 12; "117.76" reverses the sign of f_i u_i ; "120.4" divides by 5, the number of classes, instead of by 50.

Net weights (in grams) of 50 packets of tea from a Nashik packing unit:
88-100: 6, 100-112: 11, 112-124: 15, 124-136: 12, 136-148: 6.
The class width is 12. Using the step-deviation method with a = 118, find the mean weight.

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More Class 10 Mean of Grouped Data practice

Net weights (in grams) of 50 packets of tea from a Nashik packing unit:88-100: 6, 100-112: 11, 112-124: 15, 124-136: 12, 136-148: 6.The class width is 12. Using the step-deviation method with a = 118, find the mean weight.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Mean of Grouped Data practice

Net weights (in grams) of 50 packets of tea from a Nashik packing unit:
88-100: 6, 100-112: 11, 112-124: 15, 124-136: 12, 136-148: 6.
The class width is 12. Using the step-deviation method with a = 118, find the mean weight.