Using the assumed mean method a student obtained f_i d_i = 105 with f_i = 35 , and the mean came out to 68. What assumed mean a had the student chosen?

Question

Accepted Answer

65. Mean = a + f_i d_i/ f_i , so 68 = a + 105/35 = a + 3 and a = 65. "71" subtracts the correction instead of adding it; "68" wrongly assumes a equals the mean; "-37" is 68 - 105, i.e. subtracting f_i d_i without first dividing by f_i .

Using the assumed mean method a student obtained $\sum f_{i} d_{i} = 105$ with $\sum f_{i} = 35$ , and the mean came out to 68. What assumed mean a had the student chosen?

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More Class 10 Mean of Grouped Data practice

Using the assumed mean method a student obtained ∑fi​di​=105 with ∑fi​=35, and the mean came out to 68. What assumed mean a had the student chosen?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Mean of Grouped Data practice

Using the assumed mean method a student obtained $\sum f_{i} d_{i} = 105$ with $\sum f_{i} = 35$ , and the mean came out to 68. What assumed mean a had the student chosen?