- A15-35 with h = 20
- B5-15 with h = 10
- C35-60 with h = 25
- D15-35 with h = 10
Step-by-Step Solution
Cumulative: 18, 50, 95, 132, 150, so and . The first cf to reach 75 is 95, so the median lies in 15-35, whose own width is . 5-15 is the row that supplies cf = 50, not the median class. 35-60 is one row too far. The last option keeps the right class but borrows from the second class — must always be the median class's own width, especially when the widths are unequal.
Answer: A) 15-35 with h = 20