- A(4, 5)
- B(8, 10)
- C(3, 4)
- D(4, 4)
Step-by-Step Solution
Midpoint of AC = ((1+7)/2, (2+8)/2) = (4, 5). Diagonals of a parallelogram bisect each other, so BD has the same midpoint.
Answer: A) (4, 5)
In quadrilateral ABCD the diagonals AC and BD bisect each other. A school project asks: if A(1, 2), C(7, 8), and the midpoint of BD must equal the midpoint of AC, find that common midpoint.
Class 10Midpoint ApplicationsGeometry — Coordinates
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