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Riya is told that $x^{2} - (p + 3) x + 9 = 0$ has two equal roots.
Find the two possible values of $p$ .

Class 10Nature of Roots (Discriminant)Quadratic Equations

Ap = 3 or p = -9
Bp = 6 or p = -6
Cp = 0 or p = 6
Dp = 9 or p = -3

Step-by-Step Solution

Equal roots:

D = 0, (p + 3)^{2} - 4 (9) = 0 \Rightarrow (p + 3)^{2} = 36 \Rightarrow p + 3 = + 6

or

- 6 \Rightarrow p = 3

or

p = - 9

.

Answer: A) p = 3 or p = -9

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