Aa1b2−a2b1b1c2−b2c1Bb1c2−b2c1a1b2−a2b1Ca1b2−a2b1c1a2−c2a1Dc1a2−c2a1b1c2−b2c1 Step-by-Step SolutionCross-multiplication gives b1c2−b2c1x=a1b2−a2b11, so x=a1b2−a2b1b1c2−b2c1.Answer: A) a1b2−a2b1b1c2−b2c1